What is the probability of getting a club or an ace when randomly choose a card from a card deck of English?
A) 9 / 52
B) 10/52
C)
12/52 D) 16/52
E) 17/52
Answer: As events: A: "Get a club" and B "to get an ace" are NOT mutually exclusive, we proceed as follows:
P (getting a club or an ace) =
= P (getting a shamrock) + P (getting Ace) - P (get a club and an ace)
P (getting a shamrock) = 13/52
P (getting an ace) = 4 / 52
P (get a club and an ace ) = 1 / 52
P (getting a club or an ace) = 13/52 + 4 / 52 - 1 / 52 = 16/52; Alternative D)
Source: Santillana 3rd. Medium.
NEM: Tercero Medio.
Main Topic: III: Probability and Statistics.
CMO: Probability of the Union of 2 events not mutually exclusive.
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